We the Travellers 2 Class 5 Solutions Question Answer Maths Chapter 4

Students can use Class 5 Maths Solutions and Maths Mela NCERT Class 5 Maths Chapter 4 We the Travellers 2 Question Answer Solutions to explore alternative problem-solving methods.

Class 5 Maths Chapter 4 We the Travellers 2 Question Answer Solutions

We the Travellers 2 Class 5 Maths Solutions

Class 5 Maths Chapter 4 Solutions

NCERT Textbook Page 42
Making Sums Equal

In each of the following, there are two groups of numbers. Look carefully at the numbers in each group and their sums. Interchange pairs of numbers between the two groups to make their sums equal. Try to do this using the least number of moves. You could write each number on a small piece of paper.

Solution:
Sum of the numbers on the left side = 1 + 2 + 7 + 9 = 19
Sum of the numbers on the right side = 3 + 4 + 5 + 9 = 21
Difference of the sums = 21 – 19 = 2
So, we need to interchange the numbers so that the left side increases by 1 and the right side decreases by 1.
So, interchange 2 and 3.
Then, the sum of left side = 1 + 3 + 7 + 9 = 20 and the sum of right side = 2 + 4 + 5 + 9 = 20

Solution:
Sum of the numbers on the left side = 5 + 7 + 12 + 15 = 39
Sum of the numbers on the right side = 9 + 11 + 13 + 14 = 47
Difference of the sums = 47 – 39 = 8
So, we need to interchange the numbers so that the left side increases by 4 and the right side decreases by 4.
So, interchange 7 and 11.
Then, the sum of left side
= 5 + 11 + 12 + 15 = 43 and the sum of right side
= 9 + 7 + 13 + 14 = 43

Solution:
Difference between two sums
= 76 – 68 = 8
So, interchange 11 13 and 15 17 to get the sum on both sides 72.

Solution:
Do it yourself.

NCERT Textbook Page 43
Fuel Arithmetic

Question 1.
A lorry has 28 litres of fuel in its tank. An additional 75 litres is filled. What is the total quantity of fuel in the lorry?
Solution:
The total quantity of fuel in the tank is 28 l + 75 l.

Question 2.
Find the sum of 49 and 89.

Solution:

Let Us Solve

Add the following numbers. Wherever possible, find easier ways to add the pairs of numbers.
1. 15 + 79
Solution:

2. 46 + 99
Solution:

3. 38 + 35
Solution:

4. 5 + 89
Solution:

5. 76 + 28
Solution:

6. 69 + 20
Solution:

NCERT Textbook Page 44
Relationship Between Addition and Subtraction

Question 1.
Find the relationship between the numbers in the given statements and fill in the blanks appropriately.
(a) If 46 + 21 = 67, then,
67 – 21 = _______.
67 – 46 = _______.
Solution:
If 46 + 21 = 67 then,
67-21 = 46.
67-46 = 21.

(b) If 198 – 98 = 100, then,
100 + _______ = 198.
198 – _______ = 98.
Solution:
If 198-98 = 100, then,
100 + 98 = 198.
198 – 100 = 98.

(c) If 189 + 98 = 287, then,
287 – 98 = _______.
287 – 189 = _______.
Solution:
If 189 + 98 = 287 then,
287 – 98 = 189.
287 – 189 = 98.

(d) If 872 – 672 = 200, then,
200 + _______ = 872.
872 – _______ = 672.
Solution:
If 872 – 672 = 200 then,
200 + 672 = 872.
872 – 200 = 672.

Question 2.
In each of the following, write the subtraction and addition sentences that follow from the given sentence.
(a) If 78 + 164 = 242, then,
Solution:
If 78 + 164 = 242, then
242 – 78 = 164
242 – 164 = 78

(c) If 921 – 137 = 784, then,
Solution:
If 462 + 839 = 1301, then
1301 – 462 = 839
1301 – 839 = 462

(b) If 462 + 839 = 1301, then,
Solution:
If 921 – 137 = 784, then
784 + 137 = 921
921 – 784 = 137

(d) If 824 – 234 = 590, then,
Solution:
If 824- 234 = 590, then
824 – 590 = 234
590 + 294 = 824

NCERT Textbook Page 45
Let Us Solve

Question 1.
What is the difference between 82 and 37?

Solution:

Check your answer. Is 37 + _____ = 82?
Solution:
Yes, 37 + 45 = 82.

Question 2.
57 – 11 = _____
Solution:

Check: 46 + 11 = 57

Question 3.
23 – 19 = _____
Solution:

Check: 19 + 4 = 23

Question 4.
49 – 21 = _____
Solution:

Check: 21 + 28 = 49.

Question 5.
56 – 18 = _____
Solution:

Check: 38 + 18 = 56

Question 6.
93 – 35 = _____
Solution:

Check: 35 + 58 = 93

Question 7.
84 – 23 = _____
Solution:

Check: 23 + 61 = 84

Question 8.
70 – 43 = _____
Solution:

Check: 43 + 27 = 70

Question 9.
65 – 47 = _____
Solution:

Check: 47 + 18 = 65

NCERT Textbook Pages 45-46
Sums of Consecutive Numbers

Numbers that follow one another in order : without skipping any number are called consecutive numbers. Here are some examples—

Question 1.
In each of the boxes above, state whether the sums are even or odd. Explain why this is happening.
Solution:
Box 1: Since, even + odd = odd. Here one number is odd and other is even. So, all sums are odd.
Box 2: Sum of 3 consecutive numbers can be even-odd-even or odd-even-odd. Their sum alternate between even and odd depending on the starting number.
Box 3: The sum of four consecutive numbers i always gives an even number because the total of two odd numbers + two even numbers is always even. So, all sums are even.

Question 2.
What is the difference between two successive sums in each box? Is it the same throughout?
Solution:
Box 1: 5 – 3 = 2; 7 – 5 = 2; 9 – 7 = 2.
Here, the difference between two successive sums is always 2. Yes, the difference is same throughout.
Box 2: 9 – 6 = 3; 12 – 9 = 3; 15 – 12 = 3.
Here, the difference between two successive sums is always 3. Yes, the difference is same throughout.
Box 3: 14 – 10 = 4; 18 – 14 = 4; 22 – 18 = 4.
Here, the difference between two successive sums is always 4. Yes, the difference is same throughout.

Question 3.
What will be the difference between two successive sums for-
(a) 5 consecutive numbers
Solution:
1 + 2 + 3 + 4 + 5 = 15
2 + 3 + 4 + 5 + 6 = 20
3 + 4 + 5 + 6 + 7 = 25
Difference between two successive sums:
20 – 15 = 25 – 20 = 5
So, the difference is 5.

(b) 6 consecutive numbers
Solution:
1 + 2 + 3 + 4 + 5 + 6 = 21
2 + 3 + 4 + 5 + 6 + 7 = 27
3 + 4 + 5 + 6 + 7 + 8 = 33

Difference between two successive sums:
27 – 21 = 33 – 27 = 39 – 33 = 6.
So, the difference is 6.

Find the following sums without adding the numbers directly.
(a) 67 + 68 + 69
(b) 24 + 25 + 26+ 27
(c) 48 + 49 + 50 + 51 + 52
(d) 237 + 238 + 239 + 240 + 241 + 242
Solution:

NCERT Textbook Page 48
Let Us Solve

Question 1.
Find the following sums. Try not to write TTh, Th, H, T, and O at the top. Just align the digits properly, at least for the smaller numbers.
(a) 238 + 367
Solution:

(b) 1,234 + 12,345
Solution:

(c) 12 + 123
Solution:

(d) 46,120 + 12,890
Solution:

(e) 878 + 8,789
Solution:

(f) 1,749 + 17,490
Solution:

Question 2.
The great Indian road trip!
Nazrana and her friends planned a road trip across India, starting from Delhi. They first drove to Mumbai, then Goa, then Hyderabad, and finally Puri.
Look at the distances marked on the map and help them find the total distance travelled.

Solution:
In the given map, the distances between the cities are as follows:
Delhi to Mumbai = 1600 km.
Mumbai to Goa = 590 km
Goa to Hyderabad = 670 km
Hyderabad to Puri = 1055 km
Total distance = 1600 + 590 + 670 + 1055 = 3915 km.
The total distance travelled by Nazrana and her friends is 3,915 km.

Question 3.
Find 2 numbers among 5,205, 6,220, 7,095, 8,455, and 4,840 whose sum is closest to the following.
(а) 10,000
Solution:
5,205 + 4,840 = 10,045
This sum is closest to 10,000 and all other possible combinations give sums that are much higher than 10,000.

(b) 15,000
Solution:
6,220 + 8,455 = 14,675
This sum is closest to 15,000 and all other possible and combinations give sums that are much higher or much lower than 15,000.

(c) 13,000
Solution:
8,455 + 4,840 = 13,295
This sum is closest to 13,000 and all other possible combinations give sums that are much higher or much lower than 13,000.

(d) 16,000
Solution:
7,095 + 8,455 = 15,550
This sum is closest to 16,000 and all other possible combinations give sums that are much lower than 16,000.

NCERT Textbook Pages 50-51
Let Us Solve

Question 1.
Subtract the following. Try not to write TTh, Th, H, T, and O at the top. Align the digits carefully.
(a) 4,578 – 2,222
Solution:

(b) 15,324- 11,780
Solution:

(c) 5,423 – 423
Solution:

(d) 123 – 12
Solution:

(e) 77,777 – -777
Solution:

(f) 826 – -752
Solution:

Question 2.
Mary’s train journey to Delhi.
Mary is on a train journey. She starts from Kolkata with ₹ 12,540.
She spends ₹ 3,275 on food and other expenses during her trip to Varanasi. In Varanasi, her uncle gives her a gift worth ₹ 4,900. She then travels to Delhi, spending ₹ 2,645 on the train ticket. She spends ₹ 1,275 on souvenirs in Delhi. How much money is Mary left with at the end of the Delhi trip?
Solution:
(a) Mary starts her journey from Kolkata with ₹ 12,540. She spent ₹ 3,275 on food and other expenses to reach Varanasi. In Varanasi, her uncle gave her ₹ 4,900 as a gift. She then spent ₹ 2,645 on a train ticket to Delhi. In Delhi, she bought souvenirs worth ₹ 1,275.
Total money she had after receiving gift = ₹ 12,540 + ₹ 4,900 = ₹ 17,440
Total expenses during the Journey
= ₹ 3,275 + ₹ 2,645 + ₹ 1,275 = ₹ 7,195

Money left with Mary
= ₹ 17,440 – ₹ 7,195 = ₹ 10,245
Thus, Mary had ₹ 10,245 left after completing her Delhi trip.

Question 3.
Members of a school council have raised ₹ 70,500. They plan to setup a Maths Lab with some games and models worth ₹ 39,785, buy library books worth ₹ 9,545, and purchase sports equipment worth ₹ 19,548.
(a) Estimate whether the school council has raised enough money to make the purchases. Share your thoughts in the class.
(b) Check your estimate with calculations.

Solution:
(a) Estimated amount required for Math lab with some games and models (₹ 39,785) = ₹ 40,000.
Estimated amount required for library books (19,545) = ₹ 10,000
Estimated amount required for sports equipment (₹ 19,548) = ₹ 20,000
Total estimated amount
= ₹ 40,000 + ₹ 10,000 + ₹ 20,000 = ₹ 70,000
Amount raised = ₹ 70,500.
So, school council has enough money.

(b) Now, calculating actual total cost:
₹ 39,785 + ₹ 9,545 + ₹ 19,548 = ₹ 68,878
Money raised by school council = ₹ 70,500.
Balance amount = ₹ 70,500 – ₹ 68,878 = ₹ 1,622.
Therefore, school council will be left with ₹ 1,622 after all the purchases.

Question 4.
A truck can carry 8,250 kg of goods. A factory loads 3,675 kg of cement and 2,850 kg of steel on it.
(a) What is the total weight loaded onto the truck?
(b) How much more weight can the truck carry before reaching its maximum capacity?
Solution:
(a) Weight of cement = 3,675 kg
Weight of steel = 2,850 kg
Total weight of cement and steel
= 3,675 kg + 2,850 kg = 6,525 kg
So, total weight loaded onto the truck = 6,525 kg

(b) Maximum capacity of truck = 8,250 kg
Weight of cement and steel loaded on the truck = 6,525 kg
Remaining weight = 8,250 kg – 6,525 kg = 1,725 kg
So, the truck can carry 1,725 kg more before reaching its maximum capacity.

NCERT Textbook Pages 51-52
Quick Sums and Differences

Sukanta likes the numbers 10, 100, 1,000, and 10,000. He wants to figure out what number he should add to a given number such that the sum is 100 or 1,000. Help him fill in the blanks with an appropriate number.
59 + _____ = 100
Try this method for the number 59.
Solution:

Now, use this method to solve the following.
877 + ________ = 1,000 and 666 + ________ = 1,000
4,103 + ________ = 10,000 and 5,555 + ________ = 10,000
Solution:

Will this method work if the units digit is 0? What do you think? What other methods can you use to find the missing number to fill in the blanks? Share your thoughts in the class.
(a) 180 + ________ = 1,000
Solution:
180 + ________ = 1,000

(b) 760 + ________ = 1,000
Solution:
760 + ________ = 1,000

(c) 400 + ________ = 1,000
Solution:
400 + ________ = 1,000

Yes, it works, even when the unit digit is 0 Other method to find the missing number.
(a) 180 + _____ = 1,000 9 10
_____ = 1,000 – 180

(b) 760 + _____ = 1,000
_____ = 1,000 – 760

(c) 400 + = 1,000 10
_____ = 1,000 – 400

Rule: To find the missing number in an addition sentence like.
Known number + _____ = Total.
We can just subtract known number from total.

Namita likes the number 9. She wants to subtract 9 or 99 from any number. Find a way to quickly subtract 9 or 99 from any number.
(a) 67 – 9 = _____
Solution:

(b) 83 – 9 = _____
Solution:

(c) 144 – 9 = _____
Solution:

(d) 187 – 99 = _____
Solution:

(e) 247 – 99 = _____
Solution:

(f) 763 – 99 = _____
Solution:

Rule: To subtract 9 or 99 from any number. Subtract 10 or 100 from the given number and add 1 in result.

Namita wonders if she can get 9 or 99 as the answer to any subtraction problem. Find a way to get the desired answer.
(a) 32 – _____ =9
(b) 66 – _____ =9
(c) 877 – _____ = 99
(d) 666 – _____ = 99
Solution:
This is reverse subtraction
We are given the starting number and the difference and find the number that was subtracted.

We just do:
Starting number – difference = Missing number
(a) 32 – _____ = 9
_____ = 32 – 9
= 23

(6) 56 – _____ = 9
_____ = 56 – 9
= 47
(c) 877 – _____ = 99
_____ = 877 – 99
= 778

(d) 666 – _____ = 99
_____ = 666 – 99
= 567

NCERT Textbook Page 53
Let Us Think and Solve

Question 1.
Nitin likes numbers that read the same when read from left to right or from right to left. Such numbers are called palindrome numbers. The numbers 22, 363, 404, and 8,558 are some examples.

• List all palindrome numbers between 100 and 200.
• List all palindrome numbers between 900 and 1,200.
• List all palindrome numbers between 25,000 and 27,000.

Solution:

• Palindrome numbers between 100 and 200 are: 101, 111, 121,131,141,151,161, 171, 181, and 191.
• Palindrome numbers between 900 and 1,200 are: 909,919,929,939,949, 959, 969, 979, 989, 999, 1001 and 1111.
• Palindrome numbers between 25,000 and 27,000: 25052, 25152, 25252, 25352, 25452, 25552, 25652, 25752, 25852, 25952, 26062, 26162, 26262, 26362, 26462, 26562, 26662, 26762, 26862, 26962.

Question 2.
In a 3 × 3 grid, arrange the numbers 1 to 9 such that each row and each column has numbers in an increasing (inc) order. Each number should be used only once.

This time, fill the grid such that each row and column has numbers in decreasing (dec) order.

Now, fill the grids below with numbers (1-9) based on the inc (increasing) and dec (decreasing) conditions, as indicated below.

Solution:

(Answer may vary)

NCERT Textbook Page 54
Even and Odd Numbers

Question 1.
Circle the numbers that are even.
(a) 297
(b) 498
(c) 724
(d) 100
(e) 199
(f) 789
(g) 49
(h) 6,893
(i) 846
(j) HI
(k) 222
(l) 1,023
Solution:
A number is called even if its ones digit is 0, 2, 4, 6 or 8

Question 2.
Observe the given arrangement.

Add 2 to 18. What changes or does not change in the arrangement?
Add 2 to 23. What changes or does not change in the arrangement?
Solution:
In first arrangement: Paired arrangement for 18 circles. Every circle is paired, so 18 is an even.
In second arrangement: Paired arrangement for 23. One circle is unpaired, so, 23 is an odd.
If 2 is added to 18, then again every circle is paired. So, arrangement does not change.
If 2 is add to 23, then again one circle is left. So, arrangement does not change.

Question 3.
What do you notice about the sums in each of the following cases? Do you think it will be true for all pairs of such numbers? Explain your observations. You may use the paired arrangement to explain your thinking.
(a) 12 and 6 are a pair of even numbers. Choose 5 such pairs of even numbers. Add the numbers in each of the pairs.
Solution:
12 and 6 are both even numbers.
Here are 5 such pairs of even numbers and their sums.
6 + 8 = 14
4 + 8 = 12
2 + 10 = 12

4 + 12 = 16
10 + 8 = 18
(Answer may vary)

We observe that when we add two even numbers, the sum is always an even number.
Rule: Even number + even number – even number.

(b) 13 and 9 are a pair of odd numbers. Choose 5 such pairs of odd numbers. Add the numbers in each of the pairs.
Solution:
13 and 9 are both odd numbers.
Here are 5 such pairs of odd numbers and their sums.
19 + 9 = 28
11 + 7 = 18
5 + 15 = 20

13 + 7 = 20
5 + 19 = 24
(Answer may vary)
We observe that when we add two odd numbers, the sum is always an even number.
Rule: Odd number + odd number = even number

(c) 7 and 12 are a pair of odd and even numbers. Choose 5 such pairs of odd and even numbers. Add the numbers in each of the pairs.
Solution:
7 and 12 are pair of odd and even numbers. Here are 5 such pairs of odd and even numbers and their sum.
3 + 4 = 7
9 + 12 = 21
12 + 11 = 23

7 + 10 = 17
11 + 6 = 17
We observe that when we add an odd number and an even number, the sum is always an odd number.
Rule: Odd number + even number = odd number
or Even number + odd number = odd number.

NCERT Textbook Pages 54-55
Let Us Think

Question 1.
Jincy opened her piggy bank. She found 8 coins of ₹ 1, 9 coins of ₹ 2 and 5 coins of ₹ 5. She wants to buy stickers worth ₹ 38. What possible combination of coins can she use to pay the exact amount?
Solution:
Jincy has: ₹ 1 × 8 = ₹ 8 ₹ 2 × 9 = ₹ 18 ₹ 5 × 5 = ₹25
Total amount she has: ₹ 8 + ₹ 18 + ₹ 25 = ₹ 51
Now, she wants to buy stickers worth ₹ 38, so she needs to pay only ₹ 38.
One of the possible combinations of coins is:
₹ 5 × 5 = ₹ 25
₹ 2 × 6 = ₹12
₹1 × 1 = ₹ 1
Total = ₹ 25 + ₹ 12 + ₹ 1 = ₹ 38
Another possible combination is:
₹ 5 × 4 = ₹ 20
₹ 2 × 5 = ₹ 10
₹ 1 × 8 = ₹ 8.
Total = ₹ 20 + ₹ 10 + ₹ 8 = ₹ 38.
(Answer may vary)

Question 2.
Raghu is fond of his grandfather’s torch. He starts playing with it. He presses the switch once and the light turns ON. He presses it a second time and the light turns OFF. He presses the switch a third time and the light turns ON. He keeps doing this several times. Will the torch be ON or OFF after the 23rd press? How do you know?
For what number of presses will the torch be ON? For what number of presses of the switch will the torch be OFF?
Solution:
Raghu presses the switch again and again.

Every time he presses it, the torch changes its state. Let see the pattern:
1st Press → Torch turns ON
2nd Press → Torch turns OFF
3rd Press → Torch turns ON
4th Press → Torch turns OFF
and so on…
We observe that: After an odd-numbered press the Torch is ON and after an even- numbered press the Torch is OFF.
Since 23 is an odd number, so torch will be ON after the 23rd press.

Question 3.
Mountain climbing
Priyanka Mohite is the first Indian woman to climb five Himalayan peaks above 8,000 metres. In addition to that, she has also climbed mountain peaks in other parts of the world. Read the table below and answer the questions that follow.

(a) Which is the highest peak she climbed?
Solution:
The highest peak she climbed is Mount Everest of the height 8,848 metres.

(b) What is the difference in height between the highest and lowest peaks she has climbed, as per the table.
Solution:
Height of the highest peak (Mount Everest) she climbed = 8,848 m.
Height of the lowest peak (Mount Elbrus) she climbed = 5,642 m.
Difference = 8,848 – 5,642 = 3,206 m.

(c) What is the difference between heights of Mount Elbrus and Mount Kanchenjunga?
Solution:
Height of Mount Elbrus = 5,642 m
Height of Mount Kanchenjunga = 8,586 m
Difference = 8,586 – 5,642 = 2,944 m.

(d) If Priyanka was 20 years old when she summited Mount Everest in 2013, in which year was she born?
Solution:
Age of Priyanka in 2013 was 20 years.
So, her year of birth = 2013 – 20 = 1993.
Thus, she was born in 1993.

NCERT Textbook Page 56
Math Metric Mela

A grand Math Metric Mela was held at the district level to celebrate young math whizzes. Every participating student was to receive a certificate of participation. The organisers got certificates printed for each district before the Mela. The number of certificates printed and the number of students who attended the competition in each district are as follows.

For each district, find out if the number of certificates were sufficient?
If insufficient, calculate how many certificates fell short.
If extra, calculate how many certificates were in excess.
Solution:
In Chittoor, A.P.
Number of certificates printed = 18,225
Number of students attended = 18,104.
Since, 18,225 > 18,104.
So, certificates were sufficient.

Therefore, number of extra certificates = 18,225 – 18,104 = 121 In Jaunpur, U.P.
Number of certificates printed = 19,043
Number of students attended = 19,265
Since, 19,043 < 19,265.
So, certificates were insufficient.

Therefore, number of certificates fell short = 19,265 – 19,043 = 222.
In Raigad, Maharashtra Number of certificates printed = 20,863
Number of student attended = 19,974.
Since, 20,863 > 19,974.
So, certificates were sufficient.
Therefore, number of extra certificates = 20,863 – 19,974 = 889.

Let Us Do

Question 1.
Add’.
(a) 2,009 + 7,388
Solution:

(b) 26,444 + 71,111
Solution:

(c) 777 + 888
Solution:

(d) 1,234 + 1,234
Solution:

(e) 56 + 56,789
Solution:

(f) 777 + 77,777
Solution:

(g) 5,922 + 9,221
Solution:

(h) 4,321 + 8,765
Solution:

(i) 50,050 + 55,000
Solution:

Question 2.
Subtract.
(a) 458 – 226
Solution:

(b) 7,777 – 4,449
Solution:

(c) 65,447 – 47,299
Solution:

(d) 1,234 – 123
Solution:

(e) 12,345 – 1,234
Solution:

(f) 56,789 – 56
Solution:

(g) 87,326 – 11,111
Solution:

(h) 878 – 52
Solution:

(i) 749 – 222
Solution:

Question 3.
Ambrish saved ₹ 92,375 over a year to buy cows and goats. He buys a cow for ₹ 26,000 and a goat for ₹ 17,000. He also buys a milking machine for ₹ 19,873. Does he have enough money to buy these? How much more or less does he have than he needs?
Solution:
Amount saved by Ambrish = ₹ 92,375
Total cost of cow and goat = ₹ 26,000 + ₹ 17,000
= ₹ 43,000
Cost of milking machine = ₹ 19,873
Total expenditure = ₹ 43,000 + ₹ 19,873 = ₹ 62,873
Since, ₹ 92,375 > ₹ 628,73
So, he has enough money to buy these.
Now, the difference = ₹ 92,375 – ₹ 62,873 = ₹ 29,502
Thus, he has left ₹ 29,502 after the purchase.

Question 4.
A factory produces 54,000 nuts and bolts in a day. An order is placed for 85,300 nuts and bolts. How many more nuts and bolts does the factory need to produce to complete the order?
Solution:
Total order quantity of nuts and bolts = 85,300
Number of nuts and bolts already produced = 54,000.
So, number of nuts and bolts needed to produce to complete the order
= 85,300 – 54,000 = 31,300.

Question 5.
Virat Kohli has scored 27,599 runs. He has 6,758 runs less than Sachin Tendulkar. How many runs has Sachin Tendulkar scored?
Solution:
Number of runs scored by Virat Kohli = 27,599
Number of runs less than Sachin Tendulkar = -6,758
So, number of runs scored by Sachin Tendulkar = 27,599 + 6,758 = 34,357

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