Far and Near Class 5 Solutions Question Answer Maths Chapter 5

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Class 5 Maths Chapter 5 Far and Near Question Answer Solutions

Far and Near Class 5 Maths Solutions

Class 5 Maths Chapter 5 Solutions

NCERT Textbook Page 57
Let Us Find

Identify the appropriate units for measuring each of the following.

Solution:

NCERT Textbook Pages 57-58
Different Units but Same Measure

Shikha and Sonu are measuring the lengths of saris and stoles in the village weaving centre. Find which measures represent the same sari or stole. You can take help of the double number line below.


Solution:

NCERT Textbook Page 58
Let Us Compare

Question 1.
Ritika is comparing the lengths of different rods. Compare them using <, =, > signs.
(a) 456 cm ____ 5 m
Solution:
456 cm = 456 cm
and 5 m = 5 × 100 = 500 cm
Since, 456 cm < 500 cm
So, 456 cm < 5 m

(b) 55 cm + 200 cm ____ 200 cm + 54 cm
Solution:
55 cm + 200 cm = 255 cm
and 200 cm + 54 cm = 254 cm
Since, 255 cm > 254 cm
So, 55 cm + 200 cm > 200 cm + 54 cm

(c) 6 m 5 cm ____ 6 m 50 cm
Solution:
6 m 5 cm = 6 × 100 cm+ 5 cm
= 600 cm + 5 cm = 605 cm
and 6 m 50 cm = 6 × 100 cm + 50 cm
= 600 cm + 50 cm = 650 cm
Since, 605 cm < 650 cm
∴ 6 m 5 cm < 6 m 50 cm.

(d) 2 m 150 cm ____ 3 m 50 cm
Solution:
2 m 150 cm = 2 × 100 cm + 150 cm
= 200 cm + 150 cm = 350 cm
3 m 50 cm = 3 × 100 cm + 50 cm
= 300 cm + 50 cm = 350 cm
Since, 350 cm = 350 cm
So, 2 m 150 cm = 3 m 50 cm

(e) 238 cm ____ 138 cm + 1 m
Solution:
138 cm + 1 m = 138 cm + 100 cm
= 238 cm
Since, 238 cm = 238 cm
So, 238 cm = 138 cm 1 m

Question 2.
World’s tallest statue

(a) What’is the difference between the height of the tallest statue in the world and the Statue of Liberty?
(b) Identify the statues whose heights have the least difference.
(c) Identify the statues whose heights have the largest difference.
(d) The height of which statue will be equal to the height of the Statue of Unity, if it is doubled?
Solution:
(a) Height of the tallest statue (Statue of Unity) = 182 m
Height of Statue of Liberty = 93 m
So, difference of their height
= 182 m – 93 m
= 89 m

(b) Let us calculate the difference of height between two consecutive statues.
Statue of Unity (182 m) and
Spring Temple Buddha (128 m):
Difference = 54 m

Spring Temple Budda (128 m) and
Guanyin of Nanshan (108 m):
Difference = 20 m

Guanyin of Nanshan (108) and
Statue of Liberty (93 m):
Difference = 15 m

Statue of Liberty (93 m) and The
Motherland Calls (91 m):
Difference = 2 m

The Motherland Calls (91 m) and
Christ the Redeemer (38 m)
Difference = 53 m
Clearly, the least difference is 2 m.
So, the Statue of Liberty and the Motherland Calls have the least difference of 2 m.

(c) The largest difference in heights will be the difference in height between the i tallest and smallest statues that is Statue of Unity and the Christ the Redeemer.

(d) Height of statue of Unity = 182 m
So, half height Statue of Unity,
i.e., half of 182 m = 91 m which is the height of The Motherland Calls.
Hence, the double the height of The Motherland Calls will be equal to the height of Statue of Unity.

NCERT Textbook Page 59
Let Us Do

Measure 100 m and 200 m on your school playground, or any other place in and around your school, using a Long Tape. Mark these points and draw a straight line. Walk on the lines and count the number of steps. Use this relationship between the number of steps taken and distance walked to find distances around you for at least 3 locations. Wherever possible, walk and find the number of steps. Otherwise, find the distance and estimate the number of steps.

(a) Identify and write the locations that are the nearest and the farthest
from your home.
Nearest location _______________________________________________________.
Farthest location ______________________________________________________.

(b) Write the distances obtained above in increasing order.
_______________, _________________, _________________, __________________.

(c) Name a location that is equal to or more than 1,000 m from your home
(а) Identify and write the locations that are the nearest and the farthest from your home.
Nearest location Farthest location
(b) Write the distances obtained above in increasing order.
(c) Name a location that is equal to or more than 1.000 m from your home.
Solution:
Do it yourself.

Let Us Explore

When we walk 1,000 m, we say we have walked 1 km.
1,000 m = 1 km
Kilo stands for thousand. This unit is used to measure long distances.

Solution:

NCERT Textbook Page 60
Kilometre Race

Sheena and Jennifer are helping to organise a 3-km race. Help them with the arrangements for the race.

Question 1.
Water stations are to be arranged after every 500 m. How many water stations must be set up? At what positions from the starting point will these water stations be placed?
Solution:
Total distance = 3 km = 3 × 1000 m = 3000 m
The number of water stations to be set up = 3000 – 500 = 6
So, water stations will be placed at 500 m, 1000 m, 1500 m, 2000 m, 2500 m, and 3000 m.

Question 2.
Children need to stand at an interval of 300 m to direct the runners. How many children are needed? At what positions from the starting point will the children be standing?
Solution:
Total distance = 3 km = 3000 m
Distance between two children = 300 m
So, the number of children needed = 3000 -r 300 = 10
The children will be standing at, 300 m, 600 m, 900 m, 1200 m, 1500 m, 1800 m, 2100 m, 2400 m, 2700 m and 3000 m.

Question 3.
Red and blue flags are to be placed alternately at every 50 m. How many red and blue flags are needed till the finish line?
Solution:
Interval between two flags = 50 m
Total number of flags needed
= 3000 + 50 = 60 flags
Since, flags are placed alternately, starting from red.
So, the flags will be placed as : red, blue, red, blue, …
Total number of flags = 60
Since, 60 is an even, they will be equally divided.
So, 30 red flags and 30 blue flags are needed.

NCERT Textbook Pages 60-61
Let Us Do
Longest Train Journey

The longest train journey in India is by The Vivek Express which runs from Dibrugarh in Assam to Kanniyakumari in Tamil Nadu. Look at the stations on the route shown in the table below and answer the questions.

1. The total length of the route from Dibrugarh to Kanniyakumari is _______________ km.
Solution:
4,187 km

2. The distance between Vijayawada and Jalpaiguri road is _______________.
Solution:
2,800 km – 983 km = 1817 km

3. Distance between Vijayawada and Visakhapatnam is _______________.
Solution:
2,800 km – 2,450 km = 350 km

4. Which two stations are farther apart—Guwahati and Dimapur or Bhubaneswar and Jalpaiguri Road?
Solution:
Distance between Guwahati and Dimapur = 556 km – 306 km – 250 km
Distance between Bhubaneswar and Jalpaiguri Road = 2007 km – 987 km = 1,020 km
∴ 1,020 > 250
So, Bhubaneswar and Jalpaiguri Road is farther apart the Guwahati and Dimapuri.

5. What is the distance between Guwahati and Coimbatore JN?
Solution:
3,675 km – 556 km = 3,119 km

NCERT Textbook Page 61
Let Us Measure

Measure the lines in the design and write their measurements in cm and mm.

Solution:
Do it yourself.

NCERT Textbook Page 62
Let Us Do

Soak some seeds of whole moong or black or white chana overnight. Next morning, take them out and wrap them in a moist cloth to sprout them. Over the next 4 days, take out one seed each day and measure the length of sprout. For ease of measurement, you can either place the seed on a paper and mark the length of the sprout, or use a thread to find its length.

Solution:
Do it yourself

Let Us Draw

Draw lines of the following lengths in your notebook using a scale.
1. 5 mm 5 mm
2. 3 cm 6 mm
3. 8 mm 3 mm
4. 36 mm
5. 67 mm
How did you draw lines of lengths 36 mm and 67 mm? Share your thoughts in class.
Solution:
Do it yourself

NCERT Textbook Pages 63-64
Let Us Do

Question 1.
Fill in the blanks appropriately in the double number lines given below:

Solution:

Solution:

Solution:

Question 2.
Use your understanding from above to fill in the blanks appropriately.
Use your understanding from above to fill in the blanks appropriately.
(a) 4 cm 5 mm = ______ mm
Solution:
4 cm 5 mm = 4 × 10 mm + 5 mm
[As 1 m = 10 mm]
= 40 mm 5 mm
= 45 mm

(b) 89 mm = ____ cm ____ mm
Solution:
89 mm = 80 mm + 9 mm
= 8 cm 9 mm

(c) 234 cm = ____ mm
Solution:
234 cm = 234 × 10 mm
= 2340 mm

(d) 514 mm = ____ cm ____ mm
Solution:
514 mm = 510 mm + 4 mm
= 51 cm 4 mm

(e) 6 m 34 cm = ____ cm
Solution:
6 m 34 cm = 6 × 100 cm + 34 cm
[As, 1 m = 100 cm] = 600 cm + 34 cm
= 634 cm

(f) 20 m 12 cm = ____ cm
Solution:
20 m 12 cm = 20 × 100 cm + 12 cm
= 2,000 cm + 12 cm
= 2,012 cm

(g) 397 m = ______ cm
Solution:
397 m = 397 × 100 cm
= 39,700 cm

(h) 5,792 cm = ______m ______ cm
Solution:
5792 cm = 5700 cm + 92 cm
= 57 m 92 cm

(i) 9,108 cm = ______ m ______ cm
Solution:
9108 cm = 9100 cm + 8 cm
= 91 m 8 cm

(j) 34 km = _______ m
Solution:
34 km = 34 × 1000 m
= 34000 m

(k) 6,870 m = ____ km ____ m
Solution:
6,870 m = 6000 m + 870 m
= 6 km 870 m

(l) 10,552 m = ____ km ___ m
Solution:
10,552 m = 10000 m + 552 m
= 10 km 552 m

(m) 29 km 30 m = ____ m
Solution:
29 km 30 m = 29 × 1000 m + 30 m
= 29000 m + 30 m
= 29030 m

(n) 32 km 359 m = ____ m
Solution:
32 km 359 m = 32 × 1000 m + 359 m
= 32000 m + 359 m
= 32359 m

NCERT Textbook Page 66
Let Us Do

Question 1.
Rani has two red-coloured ribbon rolls, one of length 3 m 75 cm and another 2 m 25 cm long. How much ribbon does she have?
Solution:

So, Rani has 6 m long ribbon.

Question 2.
The distance from Bhopal to Sanchi is 48 km 700 m. Bhadbhada Ghat waterfall is on the way, and 17 km 900 m away from Bhopal. How far is Sanchi from the waterfall?
Solution:

Distance between Bhopal to Sanchi = 48 km 700 m
Distance between Bhopal to Bhadbhada Ghat waterfall = 17 km 900 m.
So, distance between Sanchi and waterfall = 48 km 700 m
= 30 km 800 m

Question 3.
Gulmarg Gondola in Gulmarg, Kashmir is the second longest and second highest cable car in the world. It is divided into two sections. The first section covers 2 km 300 m and the second section covers 2 km 650 m. What is the total distance covered by the cable car?
Solution:

Distance covered by cable car in first section 2 km 300 m.
And distance covered by cable car in second section = 2 m 650 m
Total distance covered by the cable car in these two sections = 2 km 300 m + 2 km 650 m
= 4 km 950 m

Question 4.
Circle the bigger length and find the difference.
(a) 11 mm and 1 cm Difference— ________________
(b) 26 mm and 2 cm Difference— ________________
(c) 20 cm and 201 mm Difference— ________________
(d) 1,020 mm and 1m Difference— ________________
(e) 2 m and 245 cm Difference— ________________
(f) 5,678 m and 6 km Difference— ________________
(g) 6 km 1,480m and 7 km 479m Difference— ________________
Solution:
(a) 1 cm = 1 × 10 mm = 10 mm 11 mm > 10 mm So, 11 mm > 1 cm
Difference = 11 mm – 10 mm = 1 mm

(b) 2 cm = 20 mm 26 mm > 20 mm Difference – 26 mm – 2 cm
= 26 mm – 20 mm = 6 mm

(c) 20 cm = 200 mm 200 mm < 201 mm So, 20 mm < 201 mm
Difference = 201 mm – 200 mm = 1 mm

(d) 1 m = 100 cm = 1000 mm 1020 mm > 1000 mm
Difference = 1020 mm -1000 mm = 20 mm

(e) 2 m = 200 cm
200 cm < 245 cm
So, 2 m < 245 cm
Difference = 245 cm – 200 cm = 45 cm

(f) 6 km = 6 × 1000 m = 6000 m
5678 m < 6000 m
Difference = 6000 m 5678 m = 322 m

(g) 6 km 1480 m = 6000 m + 1480 m
= 7480 m 7 km 479 m
= 7000 m + 479 m
= 7479 m
So,7480 m > 7479 m
So, 6 km 1480 > 7 km 479 m
So, difference = 7480 m – 7479 m = 1 m

NCERT Textbook Pages 66-67
Multiplying and Dividing Lengths

Question 1.
We need a 1 m 80 cm cloth to make a shirt for a 10-year old child. How much cloth will be needed to make shirts for 20 such children?
Solution:
20 × 1 m 80 cm = 20 × 1 m and 20 × 80 cm
= 20 m + 1600 cm (Break the quantity into m and cm and multiply. You can also convert it into cm and multiply
= 20 m + 16 m
= 36 m.
Multiplying and Dividing Lengths

Question 2.
A shop sells cloth for making bags at ₹ 100 for 5 m. How much money is needed to buy a 1 m cloth?


If 5 m cloth costs ₹ 100, then a 1 m cloth costs 100 ÷ 5 = ₹ 20.
Now, use the double number line to find the cost of the cloth or the length of cloth that we can buy at a particular cost.
Solution:

Question 3.
Anita is making an embroidery on the border of a sari. She needs aim long thread to embroider a 50 cm sari. How much thread would she need for a 5 m sari border?
A 1 m long thread costs ?50. How much money will be needed to by the thread?

Solution:
Length of Sari = 5 m = 500 cm
Length of Sari that require 1 m thread = 50 cm
Number of 50 cm in 500 cm = 500 + 50 = 10
So, Anita need 10 m of thread.
Cost of 1 m thread = ₹ 50
So, cost of 10 m thread = ₹ 50 × 10 = ₹ 500
Thus, Anita needs 10 meters of thread and the cost will be ₹ 500.

Question 4.
A road 12 km 600 m long is being laid in a town. The workers lay an equal length of road each day, and complete the work in 6 days. How much road-laying work is done on each day?
Solution:
Total length of road = 12 km 600 m
= 12,600 m
Total number of days to complete the work
= 6 days
So, the workers lay 12,600 m ÷ 6 = 2,100 m or 2 km 100 m of road each day.

NCERT Textbook Page 68
Let Us Estimate

Estimate the following. Share your reasoning in class.
1. The height of the tallest building in your neighbourhood. What did you use as a reference to estimate the height?
2. The height of the tallest tree in your neighbourhood. What did you use as a reference?
3. The depth of a well or swimming pool in your neighbourhood. How did you find out?
Solution:
Do it yourself.

Let Us Explore

In daily life, we use other units of measuring length as well. Height is usually measured in feet and inches. Look at your ruler to see if inches are also marked on it. Find out how many cm and mm equal 1 inch.

1 inch = 2 cm 5 mm
1 foot = 12 inches or 30 cm.
Solution:
Do it yourself.

NCERT Textbook Page 69
Measure Your Height

Stand against a wall and mark your height. Measure the distance between the floor and the marked point in feet and inches. Similarly, other students in the class can also measure their heights.
Find out who is the tallest student in your class. What is his or her height in feet and inches?
Solution:
Do it yourself.

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