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NCERT Solutions For Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.3

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Get Free NCERT Solutions for Class 10 Maths Chapter 8 Ex 8.3 Introduction to Trigonometry Class 10 Maths NCERT Solutions are extremely helpful while doing homework. Exercise 8.3 Class 10 Maths NCERT Solutions were prepared by Experienced LearnCBSE.in Teachers. Detailed answers of all the questions in Chapter 8 Maths Class 10 Coordinate Geometry Exercise 8.3 Provided in NCERT Textbook.

You can also download the free PDF of Chapter 8 Ex 8.3 Coordinate Geometry NCERT Solutions or save the solution images and take the print out to keep it handy for your exam preparation.

8. Introduction to Trigonometry
8.1 Introduction
8.2 Trigonometric Ratios
8.3 Trigonometric Ratios Of Some Specific Angles
8.4 Trigonometric Ratios Of Complementary Angles
8.5 Trigonometric Identities
8.6 Summary

BoardCBSE
TextbookNCERT
ClassClass 10
SubjectMaths
ChapterChapter 8
Chapter NameIntroduction to Trigonometry
ExerciseEx 8.3
Number of Questions Solved7
CategoryNCERT Solutions

NCERT Solutions For Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.3

NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.3 are part of NCERT Solutions for Class 10 Maths. Here we have given NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.3.

Question 1.
Evaluate:
NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.3 Q1
Solution:
NCERT Solutions for Class 10 Maths Chapter 8 Trigonometry Exercise 8.3 Free PDF Download

Question 2.
Show that:
(i) tan 48° tan 23° tan 42° tan 67° = 1
(ii) cos 38° cos 52° – sin 38° sin 52° = 0
Solution:
NCERT Solutions for Class 10 Maths Chapter 8 Trigonometry Exercise 8.3 Free PDF Q2

Download NCERT Solutions For Class 10 Maths Chapter 8 Introduction to Trigonometry PDF

Question 3.
If tan 2A = cot (A – 18°), where 2A is an acute angle, find the value of A.
Solution:
NCERT Solutions for Class 10 Maths Chapter 8 Trigonometry Exercise 8.3 Q3

Question 4.
If tan A = cot B, prove that A + B = 90°.
Solution:
NCERT Solutions for Class 10 Maths Chapter 8 Trigonometry Exercise 8.3 PDF Q4

Question 5.
If sec 4A = cosec (A – 20°), where 4A is an acute angle, find the value of A.
Solution:
Exercise 8.3 Class 10 NCERT Solutions Chapter 8 Trigonometry PDF Download Q5

Question 6.
If A, B and C are interior angles of a triangle ABC, then show that: sin (\frac { B+C }{ 2 }) = cos \frac { A }{ 2 }
Solution:
Exercise 8.3 Class 10 NCERT Solutions Chapter 8 Trigonometry PDF Q6

Question 7.
Express sin 61° + cos 75° in terms of trigonometric ratios of angles between 0° and 45°.
Solution:
Trigonometry Class 10 Chapter 8 Exercise 8.3 NCERT Solutions Q7

We hope the NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.3, help you. If you have any query regarding NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Exercise 8.3, drop a comment below and we will get back to you at the earliest.

The post NCERT Solutions For Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.3 appeared first on Learn CBSE.


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