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NCERT Solutions For Class 6 Maths Fractions Exercise 7.4

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NCERT Solutions For Class 6 Maths Fractions Exercise 7.4

Free download NCERT Solutions for Class 6 Maths Chapter 7 Ex 7.4 Fractions PDF for CBSE 2020 Exams.

You can also Download NCERT Solutions for Class 6 Maths to help you to revise complete Syllabus and score more marks in your examinations.

NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.4

Exercise 7.4

Question 1.
Write shaded portion as fraction. Arrange them in ascending and descending order using correct sign ‘<‘, ‘=’, ‘>’ between the fractions.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
(c) Show \frac { 2 }{ 4 } , \frac { 4 }{ 6 } , \frac { 8 }{ 6 } and \frac { 6 }{ 6 } on the number line. Put appropriate signs between the fractions given.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Solution:
(a) Total number of divisions = 8
(i) Number of shaded parts = 3
∴ Fraction = \frac { 3 }{ 8 }

(ii) Total number of divisions = 8
Number of shaded parts = 6
∴ Fraction = \frac { 6 }{ 8 }

(iii) Total number of divisions = 8
Number of shaded parts = 4
∴ Fraction = \frac { 4 }{ 8 }

(iv) Total number of divisions = 8
Number of shaded part = 1
∴ Fraction = \frac { 1 }{ 8 }
Now the fractions are:
\frac { 3 }{ 8 }, \frac { 6 }{ 8 }, \frac { 4 }{ 8 } and \frac { 1 }{ 8 } with same denominator.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
(b)(i) Total number of divisions = 9
Number of shaded parts = 8
∴ Fraction = \frac { 8 }{ 9 }
(ii) Total number of divisions = 9
Number of shaded parts = 4
∴ Fraction = \frac { 4 }{ 9 }
(iii) Total number of divisions = 9
Number of shaded parts = 3
∴ Fraction = \frac { 3 }{ 9 }
(iv) Total number of divisions = 9
Number of shaded parts = 6
∴ Fraction = \frac { 6 }{ 9 }
∴ Fractions are \frac { 8 }{ 9 }, \frac { 4 }{ 9 }, \frac { 3 }{ 9 }, \frac { 6 }{ 9 } with same denominator.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Question 2.
Compare the fractions and put an appropriate sign.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Solution:
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Here, denominators of the two fractions are same and 3 < 5.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Here, numerators of the fractions are same and 7 > 4.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Here, denominators of the two fractions are same and 4 < 5.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Here, numerators of the two fractions are same and 5 < 7.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Question 3.
Make five more such pairs and put appropriate signs.
Solution:
NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Question 4.
Look at the figures and write ’<’, or ’>’ ’=’ between the given pairs of fractions.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Make five more such problems and solve them with your friends
Solution:
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Make five more such problems yourself and solve them with your friends.

Question 5.
How quickly can you do this? Fill appropriate sign. ‘<‘, ‘=’, ‘>’.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Solution:
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Question 6.
The following fractions represent just three different numbers. Separate them into three groups of equivalent fractions, by changing each one to its simplest form.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Solution:
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Now grouping the above fractions into equivalent fractions, we have
NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Question 7.
Find answers to the following. Write and indicate how you solved them.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Solution:
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
By cross-multiplying, we get
5 x 5 = 25 and 4 x 9 = 36
Since 25 ≠ 36
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
By cross-multiplying, we get
9 x 9 = 81 and 16 x 5 =80
Since 81 ≠ 80
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
By cross-multiplying, we get
4 x 20 = 80 and 5 x 16 = 80
Since 80 = 80
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
By cross-multiplying, we get
1 x 30 = 30 and 4 x 15 = 60
NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Question 8.
Ila read 25 pages of a book containing 100 pages.
Lalita read \frac { 2 }{ 5 } of the same book. Who read less?
Solution:
Ila reads 25 pages out of 100 pages.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Lalita reads \frac { 2 }{ 5 } of the same book.
Comparing \frac { 1 }{ 4 } and \frac { 2 }{ 5 } , we get
1 x 5 = 5 and 2 x 4 = 8
Since 5 < 8
\frac { 1 }{ 4 } < \frac { 2 }{ 5 }
Hence Ila reads less pages.

Question 9.
Rafiq exercised for \frac { 3 }{ 6 } of an hour, while Rohit exercised for \frac { 3 }{ 4 } of an hour. Who exercised for a longer time?
Solution:
Rafiq exercised for \frac { 3 }{ 6 } of an hour.
Rohit exercised for \frac { 3 }{ 4 } of an hour.
Comparing \frac { 3 }{ 6 } and \frac { 3 }{ 4 } , we get
3 x 4 = 12 and 3 x 6 = 18
Since 12 < 18
\frac { 3 }{ 4 } > \frac { 3 }{ 6 }
Hence Rohit exercised for longer time.

Question 10.
In a class A of 25 students, 20 passed in first class, in another class B of 30 students, 24 passed in first class. In which class was a greater fraction of students getting first class?
Solution:
In class A, 20 students passed in first class out of 25 students.
∴ Fraction of students getting first class
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
In class B, 24 students passed in first class out of 30 students.
∴ Fraction of students getting first class
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Comparing the two fractions, we get \frac { 4 }{ 5 } = \frac { 4 }{ 5 }
Hence, both the class A and B have the same fractions.

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