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NCERT Solutions for Class 6 Maths Chapter 7 Fractions

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NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.1

Free download NCERT Solutions for Class 6 Maths Chapter 7 Exercise 7.1, Ex 7.2, Ex 7.3, Ex 7.4, Ex 7.5 and Ex 7.6 Fractions PDF for CBSE 2020 Exams.

You can also Download Class 6 Maths NCERT Solutions to help you to revise complete Syllabus and score more marks in your examinations.

Topics and Sub Topics in Class 6 Maths Chapter 6 Integers

Section NameTopic Name
7.1Introduction
7.2A Fraction
7.3Fraction on the Number Line
7.4Proper Fractions
7.5Improper and Mixed Fractions
7.6Equivalent Fractions
7.7Simplest Form of a Fraction
7.8Like Fractions
7.9Comparing Fractions
7.9.1Comparing Like Fractions
7.9.2Comparing Unlike Fractions
7.10Addition and Subtraction of Fractions
7.10.1Adding or Subtracting like fractions
7.10.2Adding or Subtracting fractions
7.10.3How do we add or Subtract mixed fractions

Fractions Class 6 Ex 7.1

Question 1.
Write the fraction representing the shaded portion.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Solution:
(i) Total number of parts = 4
Number of shaded parts = 2
∴ Fraction = \frac { 2 }{ 4 }

(ii) Total number of parts = 9
Number of shaded parts = 8
∴ Fraction = \frac { 8 }{ 9 }

(iii) Total number of parts = 8
Number of shaded parts = 4
∴ Fraction = \frac { 4 }{ 8 }

(iv) Total number of parts = 4
Number of shaded parts = 1
∴ Fraction = \frac { 1 }{ 4 }

(v) Total number of parts = 7
Number of shaded parts = 3
∴ Fraction = \frac { 3 }{ 7 }

(vi) Total number of parts = 12
Number of shaded parts = 3
∴ Fraction = \frac { 3 }{ 12 }

(vii) Total number of parts = 10
Number of shaded parts = 10
∴ Fraction = \frac { 10 }{ 10 }

(viii) Total number of parts = 9
Number of shaded parts = 4
∴ Fraction = \frac { 4 }{ 9 }

(ix) Total number of parts = 8
Number of shaded parts = 4
∴ Fraction = \frac { 4 }{ 8 }

(x) Total number of parts = 2
Number of shaded part = 1
∴ Fraction = \frac { 1 }{ 2 }

Question 2.
Colour the part according to the given fraction.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Solution:
NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Question 3.
Identify the error, if any.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions =
Solution:
(a) Since the shaded part is not half.
∴ This is not \frac { 1 }{ 2 }.

(b) Since, the parts are not equal.
∴ Shaded part is not \frac { 1 }{ 4 } .

(c) Since, the part are not equal.
∴ Shaded part is not \frac { 3 }{ 4 }.

Question 4.
What fraction of a day is 8 hours?
Solution:
Since, a day has 24 hours and we have 8 hours,
∴ Required fraction = \frac { 8 }{ 24 }

Question 5.
What fraction of a hour is 40 minutes?
Solution:
Since I hours = 60 minutes
∴ Fraction of 40 minutes = \frac { 40 }{ 60 }

Question 6.
Arya, Abhimanyu and Vivek shared lunch. Arya has brought two sandwiches, one made of vegetable and one of Jam. The other two boys forgot to bring their lunch. Arya agreed to share his sandwiches so that each person will have an equal share of each sandwich.
(a) How can Arya divide his sandwiches so that each person has an equal share?
(b) What part of a sandwich will each boy receive?
Solution:
(a) Arya has divided his sandwich into three equal parts.
So, each of them will get one part.
(b) Each one of them will receive \frac { 1 }{ 3 } part.
∴ Required fraction = \frac { 1 }{ 3 }

Question 7.
Kanchan dyes dresses. She had to dye 30 dresses. She has so far finished 20 dresses. What fraction of dresses has she finished?
Solution:
Total number of dresses to be dyed = 30
Number of dresses finished = 20
∴ Required fraction = \frac { 20 }{ 30 } = \frac { 2 }{ 3 }

Question 8.
Write the natural numbers from 2 to 12. What fraction of them are prime numbers?
Solution:
Natural numbers between 2 and 12 are;
2,3,4, 5, 6, 7, 8, 9, 10,11, 12
Number of given natural numbers = 11
Number of prime numbers = 5
∴ Required fraction = \frac { 5 }{ 11 }

Question 9.
Write the natural numbers from 102 to 113. What fraction of them are prime numbers?
Solution:
Natural numbers from 102 to 113 are;
102,103,104,105,106, 107,108, 109,110, 111, 112,113
Total number of given natural numbers = 12
Prime numbers are 103, 107, 109, 113
∴ Number of prime numbers = 4
∴ Required fraction = \frac { 4 }{ 12 } = \frac { 1 }{ 3 }

Question 10.
What fraction of these circles have X’s in them?
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Solution:
Total number’of circles = 8
Number of circles having X’s in them = 4
Required fraction = \frac { 4 }{ 8 } = \frac { 1 }{ 2 }

Question 11.
Kristin received a CD player for her birthday. She bought 3 CDs and received 5 others as gifts. What fraction of her total CDs did she buy and what fraction did she receive as gifts?
Solution:
Number of CDs bought by her from the market = 3
Number of CD’s received as gifts = 5
∴ Total number of CDs = 3 + 5 = 8
∴ Fraction of CD (bought) = \frac { 3 }{ 8 } and the fraction of CDs (gifted) = \frac { 5 }{ 8 }

Fractions Class 6 Ex 7.2

Question 1.
Draw number lines and locate the points on them.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Solution:
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
We have divided the number line from 0 to 1 into four equal parts.
C represents \frac { 2 }{ 4 } i,e., \frac { 1 }{ 2 }
B represents \frac { 1 }{ 4 }
D represents \frac { 3 }{ 4 }
and E represents \frac { 4 }{ 4 } , i.e., 1.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
We have divided the number line from 0 to 1 into eight equal parts.
B represents \frac { 1 }{ 8 }
C represents \frac { 2 }{ 8 }
D represents \frac { 3 }{ 8 }
and H represents \frac { 7 }{ 8 }

NCERT Solutions for Class 6 Maths Chapter 7 Fractions
From the above number line, we have
C represents \frac { 2 }{ 5 }
D represents \frac { 3 }{ 5 }
E represents \frac { 4 }{ 5 }
and I represents \frac { 8 }{ 5 }

Question 2.
Express the following as mixed fractions:
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Solution:
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Question 3.
Express the following as improper fractions:
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Solution:
NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Fractions Class 6 Ex 7.3

Question 1.
Write the fractions. Are all these fractions equivalent?
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Solution:
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Since all the fractions in their simplest form are not equal.
∴ They are not equivalent fractions.

Question 2.
Write the fractions and pair up the equivalent fractions from each row.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Solution:
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
The following pairs fractions:represent the equivalent fractions.
(a) and (ii) = \frac { 1 }{ 2 }
(b) and (iv) = \frac { 2 }{ 3 }
(c) and (i) = \frac { 1 }{ 3 }
(d) and (v) = \frac { 1 }{ 4 }
(e) and (iii) = \frac { 3 }{ 4 }

Question 3.
Replace NCERT Solutions for Class 6 Maths Chapter 7 Fractions in each of the following by the correct number:
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Solution:
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Question 4.
Find the equivalent fraction of \frac { 3 }{ 5 } having
(a) denominator 20
(b) numerator 9
(c) denominator 30
(d) numerator 27
Solution:
(a) Here, we require denominator 20.
Let N be the numerator of the fractions.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
∴ The required fraction is \frac { 12 }{ 20 }

(b) Here, we required numerator 9.
Let D be the denominator of the fraction.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
∴ The required fraction is \frac { 9 }{ 15 }.

(c) Here, we required denominator 30.
Let N be the numerator of the fraction.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
∴ The required fraction is \frac { 18 }{ 30 }.

(d) Here, we required numerator 27.
Let D be the denominator of the fraction.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
∴ The required fraction is \frac { 27 }{ 45 }.

Question 5.
Find the equivalent fraction of \frac { 36 }{ 48 } with
(a) numerator 9
(b) denominator 4
Solution:
(a) Given that numerator = 9
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
So, the equivalent fraction is \frac { 9 }{ 12 }.

(b) Given that denominator = 4
\frac { N }{ 4 } = \frac { 36 }{ 48 } ⇒ N x 48 = 4 x 36
⇒ N = \frac { 4 x 36 }{ 48 } = 3
So, the equivalent fraction is \frac { 3 }{ 4 } .

Question 6.
Check whether the given fractions are equivalent:
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Solution:
(a) \frac { 5 }{ 9 } and \frac { 30 }{ 54 }
We have 5 x 54 = 270
and 9 x 30 = 270
Here 5 x 54 = 9 x 30
\frac { 5 }{ 9 } and \frac { 30 }{ 54 } are equivalent fractions.

(b) \frac { 3 }{ 10 } and \frac { 12 }{ 50 }
We have 3 x 50 = 150
and 10 x 12 = 120
Here 3 x 50 ≠ 10 x 12
\frac { 3 }{ 10 } and \frac { 12 }{ 50 } are not equivalent fractions.

(c) \frac { 7 }{ 13 } and \frac { 5 }{ 11 }
We have 7 x 11 = 77 and 5 x 13 = 65
Here 7 x 11 ≠ 5 x 13
\frac { 7 }{ 13 } and \frac { 5 }{ 11 } are not equivalent fractions.

Question 7.
Reduce the following fractions to simplest form:
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Solution:
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Question 8.
Ramesh had 28 pencils, Sheelu had 50 pencils and Jamaal had 80 pencils. After 4 months, Ramesh used up 10 pencils, Sheelu used up 25 pencils and Jamaal used up 40 pencils. What fraction did each use up? Check if each has used up an equal fraction of her/his pencils.
Solution:
Ramesh used up 10 pencils out of 20 pencils.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Sheelu used up 25 pencils out of 50 pencils.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Jamaal used up 40 pencils out of 80 pencils.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Yes, each has used up an equal fractions, i.e., \frac { 1 }{ 2 }.

Question 9.
Match the equivalent fractions and write two more for each.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Solution:
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Two additional examples of equivalent fractions are
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Two additional examples of equivalent fractions are
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Two additional examples of equivalent fractions are
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Two additional examples of equivalent fractions are
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Two additional examples of equivalent fractions are
NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Fractions Class 6 Ex 7.4

Question 1.
Write shaded portion as fraction. Arrange them in ascending and descending order using correct sign ‘<‘, ‘=’, ‘>’ between the fractions.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
(c) Show \frac { 2 }{ 4 } , \frac { 4 }{ 6 } , \frac { 8 }{ 6 } and \frac { 6 }{ 6 } on the number line. Put appropriate signs between the fractions given.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Solution:
(a) Total number of divisions = 8
(i) Number of shaded parts = 3
∴ Fraction = \frac { 3 }{ 8 }

(ii) Total number of divisions = 8
Number of shaded parts = 6
∴ Fraction = \frac { 6 }{ 8 }

(iii) Total number of divisions = 8
Number of shaded parts = 4
∴ Fraction = \frac { 4 }{ 8 }

(iv) Total number of divisions = 8
Number of shaded part = 1
∴ Fraction = \frac { 1 }{ 8 }
Now the fractions are:
\frac { 3 }{ 8 }, \frac { 6 }{ 8 }, \frac { 4 }{ 8 } and \frac { 1 }{ 8 } with same denominator.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
(b)(i) Total number of divisions = 9
Number of shaded parts = 8
∴ Fraction = \frac { 8 }{ 9 }
(ii) Total number of divisions = 9
Number of shaded parts = 4
∴ Fraction = \frac { 4 }{ 9 }
(iii) Total number of divisions = 9
Number of shaded parts = 3
∴ Fraction = \frac { 3 }{ 9 }
(iv) Total number of divisions = 9
Number of shaded parts = 6
∴ Fraction = \frac { 6 }{ 9 }
∴ Fractions are \frac { 8 }{ 9 }, \frac { 4 }{ 9 }, \frac { 3 }{ 9 }, \frac { 6 }{ 9 } with same denominator.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Question 2.
Compare the fractions and put an appropriate sign.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Solution:
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Here, denominators of the two fractions are same and 3 < 5.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Here, numerators of the fractions are same and 7 > 4.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Here, denominators of the two fractions are same and 4 < 5.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Here, numerators of the two fractions are same and 5 < 7.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Question 3.
Make five more such pairs and put appropriate signs.
Solution:
NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Question 4.
Look at the figures and write ’<’, or ’>’ ’=’ between the given pairs of fractions.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Make five more such problems and solve them with your friends
Solution:
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Make five more such problems yourself and solve them with your friends.

Question 5.
How quickly can you do this? Fill appropriate sign. ‘<‘, ‘=’, ‘>’.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Solution:
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Question 6.
The following fractions represent just three different numbers. Separate them into three groups of equivalent fractions, by changing each one to its simplest form.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Solution:
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Now grouping the above fractions into equivalent fractions, we have
NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Question 7.
Find answers to the following. Write and indicate how you solved them.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Solution:
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
By cross-multiplying, we get
5 x 5 = 25 and 4 x 9 = 36
Since 25 ≠ 36
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
By cross-multiplying, we get
9 x 9 = 81 and 16 x 5 =80
Since 81 ≠ 80
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
By cross-multiplying, we get
4 x 20 = 80 and 5 x 16 = 80
Since 80 = 80
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
By cross-multiplying, we get
1 x 30 = 30 and 4 x 15 = 60
NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Question 8.
Ila read 25 pages of a book containing 100 pages.
Lalita read \frac { 2 }{ 5 } of the same book. Who read less?
Solution:
Ila reads 25 pages out of 100 pages.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Lalita reads \frac { 2 }{ 5 } of the same book.
Comparing \frac { 1 }{ 4 } and \frac { 2 }{ 5 } , we get
1 x 5 = 5 and 2 x 4 = 8
Since 5 < 8
\frac { 1 }{ 4 } < \frac { 2 }{ 5 }
Hence Ila reads less pages.

Question 9.
Rafiq exercised for \frac { 3 }{ 6 } of an hour, while Rohit exercised for \frac { 3 }{ 4 } of an hour. Who exercised for a longer time?
Solution:
Rafiq exercised for \frac { 3 }{ 6 } of an hour.
Rohit exercised for \frac { 3 }{ 4 } of an hour.
Comparing \frac { 3 }{ 6 } and \frac { 3 }{ 4 } , we get
3 x 4 = 12 and 3 x 6 = 18
Since 12 < 18
\frac { 3 }{ 4 } > \frac { 3 }{ 6 }
Hence Rohit exercised for longer time.

Question 10.
In a class A of 25 students, 20 passed in first class, in another class B of 30 students, 24 passed in first class. In which class was a greater fraction of students getting first class?
Solution:
In class A, 20 students passed in first class out of 25 students.
∴ Fraction of students getting first class
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
In class B, 24 students passed in first class out of 30 students.
∴ Fraction of students getting first class
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Comparing the two fractions, we get \frac { 4 }{ 5 } = \frac { 4 }{ 5 }
Hence, both the class A and B have the same fractions.

Fractions Class 6 Ex 7.5

Question 1.
Write these fractions appropriately as additions or subtractions.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Solution:
(a) The given figure represents the addition of
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Thus the given diagrams can be represented as
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
(b) The given figure represents the difference between 1 and \frac { 3 }{ 5 }.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Thus, the given diagrams can be represented as
NCERT Solutions for Class 6 Maths Chapter 7 Fractions

(c) The given figure represents addition of \frac { 2 }{ 6 } and \frac { 3 }{ 6 }.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Thus, the given diagrams can be represented as
NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Question 2.
Solve:
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Solution:
NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Question 3.
Shubham painted \frac { 2 }{ 3 } of the wall space in his room. His sister Madhavi helped and painted \frac { 1 }{ 3 } of the wall space. How much did they paint together?
Solution:
Fraction of wall painted by Shubham = \frac { 2 }{ 3 }
Fraction of wall painted by Madhavi = \frac { 1 }{ 3 }
Fraction of wall painted by Shubham and Madhavi
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Thus the fraction of wall painted by both = 1

Question 4.
Fill in the missing fractions.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Solution:
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Question 5.
Javed was given \frac { 5 }{ 7 } of a basket of oranges. What fraction of oranges was left in the basket?
Solution:
Fraction of basket of oranges = \frac { 5 }{ 7 }
Fraction of basket as a whole can be taken as 1.
∴ Fraction of basket of oranges left
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Thus, the required fraction = \frac { 2 }{ 7 } .

Fractions Class 6 Ex 7.6

Question 1.
Solve
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Solution:
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Question 2.
Sarita bought \frac { 2 }{ 5 } metre of ribbon and Lalita \frac { 3 }{ 4 } metre of ribbon. What is the total length of the ribbon they bought?
Solution:
Length of ribbon bought by Sarita = \frac { 2 }{ 5 } metre
Length of ribbon bought by Lalita = \frac { 3 }{ 4 } metre
∴ Length of ribbon bought by Sarita and Lalita
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Hence, the required length = \frac { 23 }{ 20 } metre

Question 3.
Naina was given 1\frac { 1 }{ 2 } piece of cake and Najma was given 1\frac { 1 }{ 3 } piece of cake. Find the total amount of cake was given to both of them.
Solution:
Piece of cake given to Naina = 1\frac 1{ 1 }{ 2 }
Piece of cake given to Najma = 1\frac 1{ 1 }{ 3 }
Piece of cake given to Naina and Najma
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Hence the total amount of piece given to both = 2\frac { 5 }{ 6 }.

Question 4.
Fill in the boxes:
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Solution:
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Here, missing number is \frac { 1 }{ 4 } more than \frac { 5 }{ 8 } .
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Here, missing number is \frac { 1 }{ 2 } more than \frac { 1 }{ 5 } .
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Here, missing number is \frac { 1 }{ 6 } less than \frac { 1 }{ 2 }.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Question 5.
Complete the addition-subtraction box.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Solution:
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Thus the box may be completed as follows:
NCERT Solutions for Class 6 Maths Chapter 7 Fractions

Question 6.
A piece of wire \frac { 7 }{ 8 } metre long broke into two pieces. One piece was \frac { 1 }{ 4 } metre long. How long is the other piece?
Solution:
Total length of the wire = \frac { 7 }{ 8 } metre
Length of one piece of wire = \frac { 1 }{ 4 } metre
∴ Length of the other piece = \frac { 7 }{ 8 }\frac { 1 }{ 4 }
LCM of 8 and 4 = 8
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Hence, the length of the other piece = \frac { 5 }{ 8 } metre.

Question 7.
Nandini’s house is \frac { 9 }{ 10 } km from her school. She walked some distance and then took a bus for \frac { 1 }{ 2 }km to reach the school. How far did she walk?
Solution:
Total distance from house to school = \frac { 9 }{ 10 } km.
Distance travelled by Nandini by bus = \frac { 1 }{ 2 } km
∴ Distance travelled by her on foot
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Hence, the distance travelled by her on foot = \frac { 2 }{ 5 }km.

Question 8.
Asha and Samuel have bookshelves of the same size partly filled with books. Asha’s shelf is \frac { 5 }{ 6 } th full and Samuel’s shelf is \frac { 2 }{ 5 } th full. Whose bookshelf is more full? By what fraction?
Solution:
Asha’s shelf is \frac { 5 }{ 6 } th full
and Samuel’s shelf is \frac { 2 }{ 5 } th full
Comparing \frac { 5 }{ 6 } and \frac { 2 }{ 5 }
LCM of 6 and 5 = 30
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Hence, Asha’s shelf is full more than Samuel’s shelf.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Hence, \frac { 13 }{ 30 } th fraction is more full of Asha’s shelf.

Question 9.
Jaidev takes 2\frac { 1 }{ 5 } minutes to walk across the school ground. Rahul takes \frac { 7 }{ 4 } minutes to do the same. Who takes less time and by what fraction?
Solution:
Jaidev takes 2\frac { 1 }{ 5 } minutes 5
Rahul takes 2\frac { 7 }{ 4 } minutes
Comparing 2\frac { 1 }{ 5 } minutes and \frac { 7 }{ 4 } minutes
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
So, the time take to cover the same distance by Rahul is less than that of Jaidev.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions
Hence, Rahul takes \frac { 9 }{ 20 } minutes less to across the school ground.

 

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