NCERT Solutions for Class 12 Maths Chapter 4 Determinants Ex 4.3
Get Free NCERT Solutions for Class 12 Maths Chapter 4 Determinants Ex 4.3 PDF in Hindi and English Medium. Sets Class 12 Maths NCERT Solutions are extremely helpful while doing your homework. Determinants Exercise 4.3 Class 12 Maths NCERT Solutions were prepared by Experienced LearnCBSE.in Teachers. Detailed answers of all the questions in Chapter 4 Class 12 Determinants Ex 4.3 provided in NCERT Textbook.
Free download NCERT Solutions for Class 12 Maths Chapter 4 Determinants Ex 4.3 PDF in Hindi Medium as well as in English Medium for CBSE, Uttarakhand, Bihar, MP Board, Gujarat Board, BIE, Intermediate and UP Board students, who are using NCERT Books based on updated CBSE Syllabus for the session 2019-20.
The topics and sub-topics included in the Determinants chapter are the following:
Section Name | Topic Name |
4 | Determinants |
4.1 | Introduction |
4.2 | Determinant |
4.3 | Properties of Determinants |
4.4 | Area of a Triangle |
4.5 | Adjoint and Inverse of a Matrix |
4.6 | Applications of Determinants and Matrices |
4.7 | Summary |
NCERT Solutions for Class 12 Maths Chapter 4 Determinants Ex 4.3
Ex 4.3 Class 12 Maths Question 1.
Find the area of the triangle with vertices at the point given in each of the following:
(i) (1,0), (6,0) (4,3)
(ii) (2,7), (1,1), (10,8)
(iii) (-2,-3), (3,2), (-1,-8)
Solution:
(i) Area of triangle =
= [1(0-3)+1(18-0)]
= 7.5 sq units
Ex 4.3 Class 12 Maths Question 2.
Show that the points A (a, b + c), B (b, c + a) C (c, a+b) are collinear.
Solution:
The vertices of ∆ABC are A (a, b + c), B (b, c + a) and C (c, a + b)
Ex 4.3 Class 12 Maths Question 3.
Find the value of k if area of triangle is 4 square units and vertices are
(i) (k, 0), (4,0), (0,2)
(ii) (-2,0), (0,4), (0, k).
Solution:
(i) Area of ∆ = 4 (Given)
= [-2k+8]
= -k+4
Case (a): -k + 4 = 4 ==> k = 0
Case(b): -k + 4 = -4 ==> k = 8
Hence, k = 0,8
(ii) The area of the triangle whose vertices are (-2,0), (0,4), (0, k)
Ex 4.3 Class 12 Maths Question 4.
(i) Find the equation of line joining (1, 2) and (3,6) using determinants.
(ii) Find the equation of line joining (3,1), (9,3) using determinants.
Solution:
(i) Given: Points (1,2), (3,6)
Equation of the line is
Ex 4.3 Class 12 Maths Question 5.
If area of triangle is 35 sq. units with vertices (2, – 6), (5,4) and (k, 4). Then k is
(a) 12
(b) – 2
(c) -12,-2
(d) 12,-2
Solution:
(d) Area of ∆ =
= [50 – 10k] = 25 – 5k
∴ 25-5k = 35 or 25-5k = -35
-5k = 10 or 5k = 60
=> k = -2 or k = 12
NCERT Solutions for Class 12 Maths Chapter 4 Determinants Hindi Medium Ex 4.3
Class 12 Maths NCERT Solutions
- Chapter 1 Relations and Functions
- Chapter 2 Inverse Trigonometric Functions
- Chapter 3 Matrices
- Chapter 4 Determinants
- Chapter 5 Continuity and Differentiability
- Chapter 6 Application of Derivatives
- Chapter 7 Integrals Ex 7.1
- Chapter 8 Application of Integrals
- Chapter 9 Differential Equations
- Chapter 10 Vector Algebra
- Chapter 11 Three Dimensional Geometry
- Chapter 12 Linear Programming
- Chapter 13 Probability Ex 13.1
More Resources for NCERT Solutions Class 12:
- Maths NCERT Solutions
- RD Sharma Class 12 Solutions
- NCERT Solutions Class 12 Physics
- NCERT Solutions Class 12 Chemistry
- NCERT Solutions Class 12 Biology
- NCERT Solutions Class 12 Hindi
- NCERT Solutions Class 12 Vistas English
- NCERT Solutions Class 12th Flamingo English
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