Get Free NCERT Solutions for Class 11 Maths Chapter 3 Trigonometric Functions Ex 3.3 PDF in Hindi and English Medium. Trigonometric Functions Class 11 Maths NCERT Solutions are extremely helpful while doing your homework. Trigonometric Functions Exercise 3.3 Class 11 Maths NCERT Solutions were prepared by Experienced LearnCBSE.in Teachers. Detailed answers of all the questions in Chapter 3 Class 11 Trigonometric Functions Ex 3.3 provided in NCERT Textbook.
- Trigonometric Functions Class 11 Ex 3.1
- Trigonometric Functions Class 11 Ex 3.2
- Trigonometric Functions Class 11 Ex 3.3
- Trigonometric Functions Class 11 Ex 3.4
- Trigonometric Functions Class 11 Miscellaneous Exercise
- त्रिकोणमितीय फलन प्रश्नावली 3.1 का हल हिंदी में
- त्रिकोणमितीय फलन प्रश्नावली 3.2 का हल हिंदी में
- त्रिकोणमितीय फलन प्रश्नावली 3.3 का हल हिंदी में
- त्रिकोणमितीय फलन प्रश्नावली 3.4 का हल हिंदी में
- त्रिकोणमितीय फलन विविध प्रश्नावली का हल हिंदी में
- Trigonometry Formulas
- Trigonometry Functions Class 11 Notes
- NCERT Exemplar Class 11 Maths Chapter 3 Trigonometric Functions
- Trig Cheat Sheet
- JEE Main Trigonometry Previous Year Questions
Free download NCERT Solutions for Class 11 Maths Chapter 3 Trigonometric Functions Ex 3.3 PDF in Hindi Medium as well as in English Medium for CBSE, Uttarakhand, Bihar, MP Board, Gujarat Board, BIE, Intermediate and UP Board students, who are using NCERT Books based on updated CBSE Syllabus for the session 2019-20.
NCERT Solutions for Class 11 Maths Chapter 3 Ex 3.3
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त्रिकोणमितीय फलन प्रश्नावली 3.3 का हल हिंदी में
प्रश्न 5.
मान ज्ञात कीजिए:
(i) sin (75°)
(ii) tan 15°
प्रश्न 10.
सिद्धि कीजिए : sin (n + 1)x sin (n + 2)x + cos (n + 1)x cos (n + 2)x = cos x.
हल :
बायां पक्ष = sin (n + 1)x sin (n + 2) x + cos (n + 1)x cos (n + 2)x
मान लीजिए (n + 2)x = A, (n + 1) x = B
= sin B sin A + cos B cos A
= cos A cos B + sin A sin B
= cos (A – B)
= cos ((n + 2) x – (n + 1) x] [A और B के मान रख कर ]
= cos (nx + 2x – nx – x)
= cos x = दाया पक्ष
प्रश्न 12.
सिद्धि कीजिए : sin² 6x – sin² 4x = sin 2x sin 10x
हल :
बायां पक्ष = sin² 6x – sin² 4x
= sin (6x + 4x) sin (6x – 4x)
( सूत्र sin² A – sin² B = sin (A + B) sin (A – B) का प्रयोग करे]
sin 10x sin 2x
sin 2x sin 10x = दाया पक्ष
प्रश्न 13.
सिद्धि कीजिए : cos² 2x – cos² 6x = sin 4x sin 8x
हल :
बायां पक्ष = cos² 2x – cos² 6x
= 1 – sin² 2x – (1 – sin² 6x)
= sin² 6x – sin² 2x
sin² A – sin² B = sin (A + B) sin (A – B)
= sin² 6x – sin² 2x
= sin (6x + 2x) sin (6x – 2x)
= sin 8x sin 4x
= sin 4x sin 8x = दाया पक्ष
प्रश्न 14.
सिद्धि कीजिए : sin 2x + 2 sin 4x + sin 6x = 4 cos² x sin 4x
हल :
बायां पक्ष = sin 2x + 2 sin 4x + sin 6x
= (sin 2x + sin 6x) + 2 sin 4x
= 2 sin 4x cos 2x + 2 sin 4x
= 2 sin 4x (cos 2x + 1)
= 2 sin 4x (2 cos² x – 1 + 1)
= 4 sin 4x cos² x
= 4 cos² x sin 4x = दाया पक्ष
प्रश्न 15.
सिद्धि कीजिए : cot 4x (sin 5x + sin 3x) = cot x (sin 5x – sin 3x)
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