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MCQ Questions for Class 10 Maths Coordinate Geometry with Answers

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Free PDF Download of CBSE Class 10 Maths Coordinate Geometry Multiple Choice Questions with Answers. Maths Multiple Choice Questions with Answers for Class 10 are Prepared Based on Latest Exam Pattern. Students can solve mcq questions for class 10 maths Coordinate Geometry to know their preparation level.

Class 10 Maths MCQ Chapter 7 Coordinate Geometry

1. The distance of the point P(2, 3) from the x-axis is
(a) 2
(b) 3
(c) 1
(d) 5

Answer/ Explanation

Answer: b
Explaination: Reason: The distance from x-axis is equal to its ordinate i.e., 3


2. The distance between the point P(1, 4) and Q(4, 0) is
(a) 4
(b) 5
(c) 6
(d) 3√3

Answer/ Explanation

Answer: b
Explaination: Reason: The required distance = \sqrt{(4-1)^{2}+(0-4)^{2}}=\sqrt{9+16}=\sqrt{25}=5


3. The points (-5, 1), (1, p) and (4, -2) are collinear if
the value of p is
(a) 3
(b) 2
(c) 1
(d) -1

Answer/ Explanation

Answer: d
Explaination: Reason: The points are collinear if area of Δ = 0
= \frac{1}{2}[-5(p + 2) +l(-2 -1) + 4(1 – p)] – 0
⇒ -5 p -10-3 + 4-4p = 0
⇒ -9p = +9
∴ p = -1


4. The area of the triangle ABC with the vertices A(-5, 7), B(-4, -5) and C(4, 5) is
(a) 63
(b) 35
(c) 53
(d) 36

Answer/ Explanation

Answer: c
Explaination: Reason: Area of ΔABC = \frac{1}{2} [x1(y2 – y3) + x2(y3 – y1) + x3(y1 – y2)]
= \frac{1}{2}[-5(-5 – 5) -4(5 – 7) + 4(7 – (-5))] = \frac{1}{2}[-5(-10) -4(-2) + 4(12)]
= \frac{1}{2}[50 + 8 + 48] = \frac{1}{2} × 106 = 53 sq. units


5. The distance of the point (α, β) from the origin is
(a) α + β
(b) α² + β²
(c) |α| + |β|
(d) \sqrt{\alpha^{2}+\beta^{2}}

Answer/ Explanation

Answer: d
Explaination: Reason: Distance of (α, β) from origin (0, 0) = \sqrt{(\alpha-0)^{2}+(\beta-0)^{2}}=\sqrt{\alpha^{2}+\beta^{2}}


6. The area of the triangle whose vertices are A(1, 2), B(-2, 3) and C(-3, -4) is
(a) 11
(b) 22
(c) 33
(d) 21

Answer/ Explanation

Answer: a
Explaination: Reason: Required area= \frac{1}{2}[1(3 + 4) -2(-4 – 2) -3(2 – 3)]
= \frac{1}{2}[7 + 12 + 3]
= \frac{1}{2} × 22 = 11


7. The line segment joining the points (3, -1) and (-6, 5) is trisected. The coordinates of point of trisection are
(a) (3, 3)
(b) (- 3, 3)
(c) (3, – 3)
(d) (-3,-3)

Answer/ Explanation

Answer: b
Explaination: Reason: Since the line segment AB is trisected
MCQ Questions for Class 10 Maths Coordinate Geometry with Answers 1


8. The line 3x + y – 9 = 0 divides the line joining the points (1, 3) and (2, 7) internally in the ratio
(a) 3 : 4
(b) 3 : 2
(c) 2 : 3
(d) 4 : 3

Answer/ Explanation

Answer: a
Explaination: Reason: Let the line 3x + y – 9 = 0 divide the line segment joining A(l, 3) ad B(2, 7) in the ratio K : 1 at point C.
MCQ Questions for Class 10 Maths Coordinate Geometry with Answers 2


9. The distance between A (a + b, a – b) and B(a – b, -a – b) is

Answer/ Explanation

Answer: c
Explaination:
MCQ Questions for Class 10 Maths Coordinate Geometry with Answers 3


10. If (a/3, 4) is the mid-point of the segment joining the points P(-6, 5) and R(-2, 3), then the value of ‘a’ is
(a) 12
(b) -6
(c) -12
(d) -4

Answer/ Explanation

Answer: c
Explaination:
MCQ Questions for Class 10 Maths Coordinate Geometry with Answers 4


11. If the distance between the points (x, -1) and (3, 2) is 5, then the value of x is
(a) -7 or -1
(b) -7 or 1
(c) 7 or 1
(d) 7 or -1

Answer/ Explanation

Answer: d
Explaination: Reason: We have \sqrt{(x-3)^{2}+(-1-2)^{2}}=5
⇒ (x – 3)² + 9 = 25
⇒ x² – 6x + 9 + 9 = 25
⇒ x² -6x – 7 = 0
⇒ (x – 7)(x + 1) = 0
⇒ x = 7 or x = -1


12. The points (1,1), (-2, 7) and (3, -3) are
(a) vertices of an equilateral triangle
(b) collinear
(c) vertices of an isosceles triangle
(d) none of these

Answer/ Explanation

Answer: b
Explaination: Reason: Let A(1, 1), B(-2, 7) and C(3, 3) are the given points, Then, we have
MCQ Questions for Class 10 Maths Coordinate Geometry with Answers 5


13. The coordinates of the centroid of a triangle whose vertices are (0, 6), (8,12) and (8, 0) is
(a) (4, 6)
(b) (16, 6)
(c) (8, 6)
(d) (16/3, 6)

Answer/ Explanation

Answer: d
Explaination: Reason: The co-ordinates of the centroid of the triangle is
MCQ Questions for Class 10 Maths Coordinate Geometry with Answers 6

 


14. Two vertices of a triangle are (3, – 5) and (- 7,4). If its centroid is (2, -1), then the third vertex is
(a) (10, 2)
(b) (-10,2)
(c) (10,-2)
(d) (-10,-2)

Answer/ Explanation

Answer: c
Explaination: Reason: Let the coordinates of the third vertex be (x, y)
MCQ Questions for Class 10 Maths Coordinate Geometry with Answers 7

 


15. The area of the triangle formed by the points A(-1.5, 3), B(6, -2) and C(-3, 4) is
(a) 0
(b) 1
(c) 2
(d) 3/2

Answer/ Explanation

Answer: a
Explaination: Reason: Area of ΔABC = \frac{1}{2} [-1.5(-2 – 4) + 6(4 – 3) + (-3) (3 + 2)] = \frac{1}{2} [9 + 6 – 15] = 0. It is a straight line.


16. If the points P(1, 2), B(0, 0) and C(a, b) are collinear, then
(a) 2a = b
(b) a = -b
(c) a = 2b
(d) a = b

Answer/ Explanation

Answer: a
Explaination: Reason: Area of ΔPBC = 0
\frac{1}{2}[1(0 – b) + 0(6 – 1) + a(2 – 0)] = 0
\frac{1}{2}[-6 + 2a] = 0
⇒ -b + 2a = 0
∴ 2a = b


We hope the MCQ Questions for Class 10 Maths Coordinate Geometry with Answers with Solutions, help you. If you have any query regarding Maths Class 10 Maths MCQ Chapter 7 Coordinate Geometry with Solutions, drop a comment below and we will get back to you at the earliest.

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